Thread: Problem with input

Say if i had a user enter a character

Code:

printf("Enter operation code: ");
scanf("%s", operCode);

if(operCode == 's')
{
some code to run
}

if(operCode == 'i')
{
some code to run
}

if(operCode == 'u')
{
some code to run
}

if(operCode == 'p')
{
some code to run
}

if(operCode == 'q')
{
some code to run
}

now say none of those characters were entered, why does this always return true or have no effect reguardless if i entered a right caracter ???

Code:

if(operCode != 'i', 's', 'u', 'p', 'q')
{
some code to run
}

how would i tell it...if none of these letters weren't entered, then run the condition ?! i've tried using both ' ' and " "...i also tried having it run first and last but no luck

thanks for the help

Code:

if(operCode != 'i', 's', 'u', 'p', 'q')

this statement evaluates to 'q' and 'q' is alwais true.
you want

Code:

if(operCode != 'i' && operCode != 's' && operCode !=  'u' && operCode !=  'p' && operCode !=  'q')

Kurt

sweet that last one worked...thanks alot for the help people really appreciate it !

Originally Posted by Prelude

>scanf("%s", operCode);
It doesn't work like that. You need to specify a comparison for each and every condition and link them with logical operators:

Code:

if ( operCode != 'i'
  && operCode != 's'
  && operCode != 'u'
  && operCode != 'p'
  && operCode != 'q' )
{
  /* Some code to run */
}

Or use a nice neat switch statement:

Code:

switch(operCode){
    case 's':
    case 'u':
    case 'p':
    case 'q':
        /* some code to run */
        break;
}