Thread: Program runs and calculates before all integers are input

Hi People
I am trying to run the following program in at the command line in Ubuntu and it prompts for the first number ok but as soon as I press enter to input the next number it runs the program with an erroneous results.

Code:

#include <stdio.h>

int main()
{
	int num1, num2;
	int product;

	printf("Please enter the first integer number: ");
	scanf("%D%*c", &num1);

	printf("Please enter the second integer number: ");
	scanf("%D%*c", &num2);

	product = num1 * num2;

	printf("The product of the two numbers is: %d\n", product);
	return(0);
}

Please enter the first integer number: 1
Please enter the second integer number: The product of the two numbers is: 0

the same program works perfectly well in a terminal in windows but not in Linux where I would prefer to be working.
Can anybody tell me why this is happening

> nani?
was?

Ok I have had a look at that and tried fgets and fputs instead of scanf but still no joy.
The code I have be given was supplied by my lecturer which is interesting. I am still bemused that scanf works ok in bcc32 in windows but not in gcc in a terminal in linux! Bizarre.
Can I get a little more guidance.

Ok Thanks for that. My first crack at C so I am just not use to the syntax at all having come from VB

Nani means "what?" though i dont know what ¿Qué? means so i googled it:
When used with the verb ser, cuál and qué can both mean "what," but they are not interchangeable. Cuál is more common, and is used to indicate a selection, ...