Thread: Printing Armstrong Numbers from 1-500

Code:

/*
Write a program to print out all Armstrong numbers between 1 and 500. 
If sum of cubes of each digit of the number is equal to the number itself, 
then the number is called an Armstrong number. 
For example, 
153 = (1*1*1) + (5*5*5) + (3*3*3)
*/


#include<stdio.h>
main()
{
	int number, temp, digit1, digit2, digit3;

	printf("Printing all Armstrong numbers between 1 and 500:\n\n");

	number = 001;

	while (number <= 500)
	{
		digit1 = number%10;
		digit2 = (number%100) - ((number/100)*10);
		digit3 = number%1000;

		temp = (digit1*digit1*digit1) + (digit2*digit2*digit2) + (digit3*digit3*digit3);

		if (temp == number)
		{
			printf("\nAmstrong Number:%d", temp);
		}

		number++;
	}
}

Whats wrong with this code??

It does not give any output at all!

Your digit extraction perhaps?

Use a series of /10 and %10

Okay..i will try that..

Also try printing out your digits (or examine them with the debugger) as you go.

Worked

I changed the digit extraction scheme to this:

Code:

digit1 = number - ((number / 10) * 10);
digit2 = (number / 10) - ((number / 100) * 10);
digit3 = (number / 100) - ((number / 1000) * 10);

But still...


number%10 --- should extract the last number
and
number%100 -- should have extracted the first number (of a three digit number), isn't it?

123 % 100 gets you 23
23 / 10 gets you 2