Printing Armstrong Numbers from 1-500

This is a discussion on Printing Armstrong Numbers from 1-500 within the C Programming forums, part of the General Programming Boards category; Code: /* Write a program to print out all Armstrong numbers between 1 and 500. If sum of cubes of ...

  1. #1
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    Printing Armstrong Numbers from 1-500

    Code:
    /*
    Write a program to print out all Armstrong numbers between 1 and 500. 
    If sum of cubes of each digit of the number is equal to the number itself, 
    then the number is called an Armstrong number. 
    For example, 
    153 = (1*1*1) + (5*5*5) + (3*3*3)
    */
    
    
    #include<stdio.h>
    main()
    {
    	int number, temp, digit1, digit2, digit3;
    
    	printf("Printing all Armstrong numbers between 1 and 500:\n\n");
    
    	number = 001;
    
    	while (number <= 500)
    	{
    		digit1 = number%10;
    		digit2 = (number%100) - ((number/100)*10);
    		digit3 = number%1000;
    
    		temp = (digit1*digit1*digit1) + (digit2*digit2*digit2) + (digit3*digit3*digit3);
    
    		if (temp == number)
    		{
    			printf("\nAmstrong Number:%d", temp);
    		}
    
    		number++;
    	}
    }

    Whats wrong with this code??

    It does not give any output at all!

  2. #2
    and the hat of wrongness Salem's Avatar
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    Your digit extraction perhaps?

    Use a series of /10 and %10
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.
    I support http://www.ukip.org/ as the first necessary step to a free Europe.

  3. #3
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    Okay..i will try that..

  4. #4
    and the hat of wrongness Salem's Avatar
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    Also try printing out your digits (or examine them with the debugger) as you go.
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.
    I support http://www.ukip.org/ as the first necessary step to a free Europe.

  5. #5
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    Worked

    I changed the digit extraction scheme to this:

    Code:
    digit1 = number - ((number / 10) * 10);
    digit2 = (number / 10) - ((number / 100) * 10);
    digit3 = (number / 100) - ((number / 1000) * 10);

  6. #6
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    But still...


    number%10 --- should extract the last number
    and
    number%100 -- should have extracted the first number (of a three digit number), isn't it?

  7. #7
    and the hat of wrongness Salem's Avatar
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    123 % 100 gets you 23
    23 / 10 gets you 2
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.
    I support http://www.ukip.org/ as the first necessary step to a free Europe.

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