Command line input

[Moony]

Hi,
I don't know how to fix this:

input: prog -a-a
output:
a
prog: unknown option -- -
a

while (( c = getopt (argc, argv, "ab")) != -1)
 {
    switch (c)
    {
       case 'a':
       printf ("a...\n");
       break;

       case 'b':
       printf("b...\n");
       break;

       case '?':
       default:
       usage();
       break;
    }
 }

[kris.c]

Dont u think there's something wrong with using argc and argv that way...
main() takes in two arguments.One is an integer that specifies the number of arguments at the prompt
and the other argument is a char *argv[] in which each element of the array is a pointer to a different char array....

[Moony]

Dont u think there's something wrong with using argc and argv that way...
main() takes in two arguments.One is an integer that specifies the number of arguments at the prompt
and the other argument is a char *argv[] in which each element of the array is a pointer to a different char array....

so...

[Moony]

I think that the usage of getopt() is correct ...

[kris.c]

yeah, but u r giving

prog -a-a.. at the prompt,arent u?? and if u r just specifying the argument what is that " - " doing there?

[kris.c]

ok , I understand ur problem, this is what u might have intended to do :

prog -a -a

this gives u the reqd o/p..

[Moony]

ok , I understand ur problem, this is what u might have intended to do :

prog -a -a

this gives u the reqd o/p..

I am working with all possibilities that the user may write:
prog -a-a -- which displays what I wrote in my first post
How to cover this situation?

[Moony]

No help!

[itsme86]

getopt() is designed to be used a particular way. If you want to parse command line options in some other fashion then you should create your own parser.

IMHO, telling the user that -a-a isn't valid is handling it.

[Moony]

Thanks. I got what you mean