pointer to pointer how do i solve following problem?

hi everybody
in a program i have the following code

typedef struct game {
linked_list *list; //datastruktur som jag definierat själv
} game;

in the main program i have following
game *g1 =malloc(...)
linked_list *link=malloc(...)

if i want to change the content of *g1 from a function i have to do it from a function like this

void addInList (game **g, linked_list ** li) {
*g->list=*li;
}
and when i call the function i do it with following code
addInList(&g, &link)
can somebody tell me why this piece of code doesn't work and how should the corect syntax be

You actually do not need to pass-by-pointer.

Code:

---

void addInList(game * g, linked_list * li)
{
        g->list = li;
}

---

But the way that you did it should not make it not work. Only thing I can um, maybe see, is that you say g instead of g1? Maybe the problem is elsewhere.

Use [code][/code] tags.

What do you mean by "it doesn't work"? It doesn't compile? It doesn't run?

Tonto is right; there's nothing wrong with your code *, although you don't need pointers to pointers. Post some more of your code.

[edit] * Other than a precendence issue. :) http://www.cppreference.com/operator_precedence.html [/edit]

Code:

---

void addInList (game **g, linked_list ** li) {
*g->list=*li;
}

---

I believe the 2nd line actually needs to be: (*g)->list=*li;. Precedence and all...

I know that to dereference a pointer to a struct to get to a member (without using ->) you need to do (*ptr).member and I'm assuming that -> has the same precedence as .

You're right, it does. As written, it's the same as

Code:

---

*(g->list)=*li;

---

which probably wasn't what was intended.

OMG!