Hi,
I am writing a utility that processes a system file , but this file exists in all drives.
C:\file1
D:\file1
E:\file1
My question: how can I process all files at the same time since when I want to run my utility I pass the path for one file
Note: The system file may contains different content according to the drive, but it has the same name for all drivesCode:f=fopen("C:\\file1","r");
Thankx
You can't open multiple files with a single fopen all. You will need to call it multiple times. Fill an array with your file and location, and modify it before each call to change the drive letter.
Quzah.
Hope is the first step on the road to disappointment.
Please, explain more
Fill an array with your path. That is, instead of passing a string literal, pass an array. Now change the C to a D to an E to ... each time you call the function.Code:char filename[] = "c:\\foo.bar"; size_t x; FILE *fp; for( x = 0; x < numdrives; x++ ) { fp = fopen( filename, "r" ); if( fp ) { process_file( fp ); fclose( fp ); } filename[0]++; }
Quzah.
Hope is the first step on the road to disappointment.
http://faq.cprogramming.com/cgi-bin/...&id=1043284392
And run your program as
myprog C:\file1 D:\file1 E:\file1
Just have a loop to open and close each argv[n] in turn.
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
