Thread: compile error: implicit return at end of non-void function (warning)...

Hi,

I am using pacific c compiler and get that error when compiling. I also used DEVC++ compiler (which can also compile c programs ) and get the error of illegal operation of program.

Here is the code, pls help out, and tell me where i went wrong, thnx in advance.



code:--------------------------------------------------------------------------------
/* Calculates and prints parking charges. */

#include <stdio.h>

float calculateCharges( float );

int main()
{
float timeParked1, timeParked2, timeParked3;

printf( "Car %2d - hours parked: ", 1 ); /* Car 1 */
scanf( "%f", timeParked1 );
printf( "Car %2d - hours parked: ", 2 ); /* Car 2 */
scanf( "%f", timeParked2 );
printf( "Car %2d - hours parked: ", 3 ); /* Car 3 */
scanf( "%f", timeParked3 );

printf( "%2s%6s%6s", "Car", "Hours", "Charge" );
printf( "\n%2d%6.2f%6.2f", 1, timeParked1, calculateCharges( timeParked1 ) );
printf( "\n%2d%6.2f%6.2f", 2, timeParked2, calculateCharges( timeParked2 ) );
printf( "\n%2d%6.2f%6.2f", 3, timeParked3, calculateCharges( timeParked3 ) );

return 0;
}


float calculateCharges( float parked )
{
float fee;

if ( parked <= 3 )
return 2.00;
if ( parked > 3 ) {
fee = ( parked - 3 ) * 0.50 + 2;
return fee;
}
if ( parked = 24 )
return 10.00;
}

i edited the code and fixed a few more bugs, then there's no compile error. But the output is really werid, all the spacing are not correct. The edited code is:

Code:

/* Calculates and prints parking charges. */

#include <stdio.h>

float calculateCharges( float );

int main()
{
   float timeParked1, timeParked2, timeParked3;

   printf( "Car %2d - hours parked: ", 1 );   /* Car 1 */
   scanf( "%f", &timeParked1 );
   printf( "Car %2d - hours parked: ", 2 );   /* Car 2 */
   scanf( "%f", &timeParked2 );
   printf( "Car %2d - hours parked: ", 3 );   /* Car 3 */
   scanf( "%f", &timeParked3 );

   printf( "%s%6s%6s", "Car", "Hours", "Charge" );
   printf( "\n%d%6f%6.2f", 1, timeParked1, calculateCharges( timeParked1 ) );
   printf( "\n%d%6f%6.2f", 2, timeParked2, calculateCharges( timeParked2 ) );
   printf( "\n%d%6f%6.2f", 3, timeParked3, calculateCharges( timeParked3 ) );

   return 0;
}


float calculateCharges( float parked )
{
   float fee;
	
   if ( parked <= 3 )
      return 2.00;
   else if ( parked > 3 ) {
      fee = ( parked - 3 ) * 0.50 + 2;
      return fee;
   }
   else if ( parked == 24 )
      return 10.00;
   else
      return 0;
   
}

The output of the program is:

Car - 1 hours parked: 2
Car - 2 hours parked: Car 3 - hours parked: Car HoursCharge
1(non-float printf) (n
2(non-float printf) (n
3(non-float printf) (n


pls help thnx

Your program expects you to put in values for each of three cars. If for some car no input is available, then input 0. This will help. Or, before asking for input, ask the number of cars for which input should be done.

You should work a little bit on your spaces. The middle row is added onto the number of car, this can be solved by making it %6.2f instead of %6f. And the word Charges has 6 characters, so it will be added on hours. Try 8 instead of 6.

And there still is a logical error in your program:

else if (parked > 3)
{
fee = ( parked - 3 ) * 0.50 + 2;
return fee;
}
else if ( parked == 24 )
return 10.00;
else
return 0;

If parked>3, then it will do some calculations and return. But... you will never ever reach parked==24, since 24>3. So if parked==24, then it will go into the if (parked>3) and then return!

A possible solution:

float calculateCharges( float parked )
{
float fee;

if ( parked <= 3 )
flee = 2.00;
else /* parked > 3 */
{
if (parked == 24)
fee = 10.00;
else
fee = (parked - 3) * 0.50 + 2;
}

return fee;
}

Shiro thnx a lot, problem fixed beautifully.