question about declaration precedence

hello,

can anyone explain to me why when i declare this array:

Code:

---

int myArray[] = {0-9};

---

before this array of pointers to strings:

Code:

---

char *engNumbers[] = { "zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine" };

---

that i get (null) values for the strings, but if i declare the array of pointers to strings first it works properly?

here is the non-working code:

Code:

---

#include <stdio.h>
#include <string.h>

int main()
{
    int myArray[] = {0-9};

    char *engNumbers[] = { "zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine" };

    int h, i, j, k;

    int myProb = 17150;

    for (i = 0; i < 10; i++)  // initialize the array
    {
        myArray[i] = 0;
    }

    for (h = 0; h < 10; h++)
    {
        printf("%s\n", engNumbers[h]);
    }

    while (myProb != 0)
    {
        j = (myProb % 10);  // get the modulus and
        myArray[j]++;      // assign it to the proper array element
        myProb = (myProb / 10);  // do the division so you can move on
    }

    for (k = 0; k <= 9; ++k)
    {
        if (myArray[k] == 1)
            printf("There is one %d in the number.\n", k);
        else if (myArray[k] > 1)
            printf("There are %s %d's in the number.\n", engNumbers[k + 1], k);
    }
   
    return 0;
}

---

and here is the working code:

Code:

---

#include <stdio.h>
#include <string.h>

int main()
{
    char *engNumbers[] = { "zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine" };
   
    int myArray[] = {0-9};
   
    int h, i, j, k;

    int myProb = 17150;

    for (i = 0; i < 10; i++)  // initialize the array
    {
        myArray[i] = 0;
    }

    for (h = 0; h < 10; h++)
    {
        printf("%s\n", engNumbers[h]);
    }

    while (myProb != 0)
    {
        j = (myProb % 10);  // get the modulus and
        myArray[j]++;      // assign it to the proper array element
        myProb = (myProb / 10);  // do the division so you can move on
    }

    for (k = 0; k <= 9; ++k)
    {
        if (myArray[k] == 1)
            printf("There is one %d in the number.\n", k);
        else if (myArray[k] > 1)
            printf("There are %s %d's in the number.\n", engNumbers[k + 1], k);
    }

    return 0;
}

---

i'm using gcc 4.0.1.

thanks!

What exactly is

Code:

---

int myArray[] = {0-9};

---

...supposed to do? It looks to me like it would create a one-element array with the value -9. I thought array initializers had to be constants though. Hmmmm...

It certainly won't create:
myArray[0] = 0;
myArray[1] = 1;
...
myArray[9] = 9;

...like it looks like you're trying to make it do. If you want an un-initialized 10-element array then declare it like:

Code:

---

int myArray[10];

---

thank you itsme,

i knew it was something silly i was doing.

Was that just a wild guess that 0-9 would work or are you a FORTRAN programmer or something?

hi sly,

i think i just got confused between declaring an array and declaring an array of pointers. i wanted to make sure to get the array of pointers correct, so i think i was paying less attention when i made the actual array of integers.

what more can i say? i'm certainly not a FORTRAN programmer.