Thread: problem with function

Hey,
When I run the following program, the output gives 0 for the btw. I probably made an error in typing the program, but I can't seem to find it.

Lynn

Code:

/*fbtw.c*/
#include <stdio.h>
int btw21(int x);
void main (void)
{
	int faktuurbedrag,btw,inclusief;
	printf("Geef het faktuurbedrag:");
	scanf("%d%*c",&faktuurbedrag);
	btw=btw21(faktuurbedrag);
	inclusief=faktuurbedrag+btw;
	printf("BTW           = %5d\n",btw);
	printf("inclusief btw= %5d\n",inclusief);
}
int btw21(int a)
{
	int b;
	b=a*0,21+0,5;
	return b;
}

0 is the expected output for this program.
you need to use a floating point type for the calculations to get a different ( more accurate ) result.
Kurt

Thanks. I changed it into float, but it still gives 0.

Lynn

That is because the the compiler expects '.' not ',' as decimal separator.

Code:

b=a*0,21+0,5;

this are actually 3 statements
1) b=a*0
2) 21+0
3) 5

Kurt

This was the problem indeed. Thank you very much for solving it.

Lynn