Thread: Newbie question, trouble entering value into switch from scanf function

I'm having trouble inputing a value into the switch control from scanf. I'm completely lost as to what the problem maybe.

Code:

#include <stdio.h>

int code = 0, hours = 0;
float salary = 0, wage = 0, base = 0;


int main()
   {

   while ( code != 6 )
      {

      printf("Enter number 1-6(6 to exit): ");
      scanf("%d", &code);
/*---------Test code below------*/
      printf("%d", code);

      switch (code)
         {

         case '1':
            printf("Enter weekly salary: ");
            scanf("%lf", &salary);
            printf("Well there you, you make %.2f a week\n", salary);
            break;
/*
         case '2':
            printf("Enter hourly wage: ");
            scanf("%lf", &wage);
            printf("Enter hours worked in week: ");
            scanf("%d", &hours);

            if (hours > 40)
               salary = ( (hours - 40) * 1.5 + 40 ) * wage;
            else
               salary = (float) hours * wage;

            printf("You made %.2f this week\n", salary);
            break;

         default:
            break;
*/
         }

      }


   return 0;
   }

Thank you!

Hmmm, I wonder why it somewhat worked with getchar but not with scanf.

crystal clear

if you dont want to change int code = 0 to char code = '0' or case '1' to case 1: write:
case '1'-'0': ...
case '2'-'0': ...
...
its funny

vangmor, the next time you give advice, make it correct advice. A switch statement might compile like that, but it won't work. I'm surprised it doesn't warn you that the case value isn't constant.