Thread: Two Dimensional Array Of Characters

that's strange, I can't see why it wouldn't work.

Of course if you are reading multiple things in you will need to keep track of which element in the array you are up to, so you will need to do

fgets(arrayA[i], sizeof(arrayA[i]), stdin)

and increment i accordingly.

I compiled it and ran it and it worked fine for me.

> It doesnt let me enter the code, it just skipps to the next part where i enter the time.

This is where I used to suggest fflush, but that is bad apparantly. Use fgets and sscanf to get the time

Code:

int Info(char arrayA [][9], int arrayB[], int count)
{
	char buf[BUFSIZ];
	
	printf("Enter the code for %d:  ", count);
	fgets(arrayA[0], sizeof(arrayA[0]), stdin);
	printf("Enter the time %d:  ", count);
	fgets( buf, BUFSIZ, stdin);
	sscanf( buf, "%d", arrayB);
}

Though, you're always writing into the first element of each array, which I imagine is not what you want to do...

There seems to be a lot of confusion over what pointer to arrays are, especially the difference between a ** and [][N] parameter.

Code:

#include<stdio.h>

void info(char arrayA[][9], int arrayB[], int count ) {
  char buff[BUFSIZ];

  printf( "pointer=%u\n", sizeof(arrayA) );
  printf( "array row (char[9])=%u\n", sizeof(arrayA[0]) );
  printf( "single element (char)=%u\n", sizeof(arrayA[0][0]) );
  printf( "pointer=%u\n", sizeof(arrayB) );
  printf( "single element (int)=%u\n", sizeof(arrayB[0]) );

  printf("Enter the code for %d:  ", count);
  fgets( buff, BUFSIZ, stdin );
  sscanf( buff, "%8s", arrayA[count] );
  printf("Enter the time %d:  ", count);
  fgets( buff, BUFSIZ, stdin );
  sscanf( buff, "%d", &arrayB[count] );
}

int main ( void ) {
  char arrayA[5][9];
  int arrayB[5];
  info( arrayA, arrayB, 1 );
  printf( "%s %d\n", arrayA[1], arrayB[1] );
  return 0;
}


$ ./a.exe
pointer=4
array row (char[9])=9
single element (char)=1
pointer=4
single element (int)=4
Enter the code for 1:  hello
Enter the time 1:  4
hello 4