Thread: getting rid of newline

If the newline is because of fgets it is right before the null character. So do what you said except instead of using strlen(string) you add a minus one.

Code:

string[strlen(string)-1);

so if you got a string, "This is a string" using fgets then the array would be "T h i s i s a s t r i n g \n \0". This would take the string length which is 18 and then subtract one so that it is now on the \n and then replace it with \0.
~Sven

Code:

n = strlen( str1 )

for ( i = 0; i < n; i++ )
{
    if ( str1[i] == '\n' )
    {
         str1[i] = '\0';
    }
}

That code is raw, but that's the way you should be tackling the problem, in my opinion.

Are you by any chance passing a string literal? How about posting your full code, instead of just some random bits? Also "not working" doesn't tell us anything. Post a compilable example, complete with the input you give and the out put you get.

I hate having to teach people how to think for themselves.


Quzah.

Maybe it's your compiler?

This runs fine on mine:

Code:

int main(int argc, char *argv[])
{
    int i, n;
    char str1[] = "balls\nsackaroo\n";
    
    n = strlen( str1 );
    
    for ( i = 0; i < n; i++ )
    {
        printf("%c", str1[i]); 
    }
    
    
    for ( i = 0; i < n; i++ )
    {
        if ( str1[i] == '\n' )
        {
             str1[i] = '\0';
        }
    }
    
    printf("\n\n");
    
    for ( i = 0; i < n; i++ )
    {
        printf("%c", str1[i]); 
    }
    
    
    system("PAUSE");	
    return 0;
}

Though, the null characters print as spaces.