understand lnked list

Hi can someone explain me this function

Code:

struct Node{
char name[39];
sruct Node *next Ptr;}
typedef struct Node Node;

void insert(Node** firstHndl,char s[])
{Node*prt malloc(sizeof(char(Node));
strcpy(ptr->name,s);
ptr->nextPtr=*firstHndl;
*firstHndl=ptr;}

The bolded code this what I need to understand. how the insertion is made.
Thank you
B.

Draw a list on paper.
"animate" what happens to the pointers as you "run" that code by hand.

first of all u need a proper indentation. this is how it looks when properly indented

Code:

struct Node
{
    char name[39];
    struct Node *next Ptr;
}typedef struct Node Node;

void insert(Node** firstHndl,char s[])
{
    Node*prt malloc(sizeof(char(Node));
    strcpy(ptr->name,s);
    ptr->nextPtr=*firstHndl;
    *firstHndl=ptr;
}

> The bolded code this what I need to understand. how the insertion is made.
this last two line are the one which actually forms the lined list. if u can think of soemthing like follow

Code:

|____|__| -> |_____|__| -> |____|_/_|   <-- assume a linked list
   ^
  *firstHndle

|_____|_/_|   |_____|__| -> |_____|__| -> |____|_/_|
                 ^
                 *firstHndle
 ptr->nextPtr=*firstHndl;
|_____|__| -> |_____|__| -> |_____|__| -> |____|_/_|
                ^
               *firstHndle

*firstHndl=ptr;
|_____|__| -> |_____|__| -> |_____|__| -> |____|_/_|
  ^
*firstHndle

if u go thorugh the diagram clearly u will understand what that two statment means

EDIT: Tried my level best to keep the *firstHndle to point to the right node

ssharish2005