Thread: casting a pointer as static

Hi,
Why can't I get static to work here? Where static is highlighted in blue.

Code:

#include <stdio.h>

main()

{
      char source[] = "qazwsxedcrfvtgbyhnujmikolp";   
      char * src_ptr;                                    
    
      char target[] = "lkjhgfdsaqwertyuiopmnbvcxz";    
      char * tar_ptr;
    
      char temp[51];
      char * temp_ptr;
      
     
      int counter=0,
          i=0,
          t=0;
      
      printf("\nPlease enter a line of text: ");
      gets(temp); 
 
 for(temp_ptr = temp; *temp_ptr != '\0'; ++temp_ptr)
 ++t;
      
while(i<t)
            
 {          
 

      for(src_ptr = source, static temp_ptr = temp; *temp_ptr && *src_ptr != '\0';)
      
         {
           if(*temp_ptr != *src_ptr)
           {
             ++src_ptr;
             continue;
           }
              
           else
           {       
             ++temp_ptr;    
              break;                              
           } 
         }
           ++i;       
 }
 
 getchar();

}

Perhaps because C(89) does not allow inline declarations? Or perhaps because that symbol was previously decloared? What are you attempting to accompish?

I meant, "What is it that you expect adding the keyword static to do for you?"

Have you broken things into separate functions yet?

Have you seen the FAQ? (Obviously not, because there you would learn never to use ]gets.)

Bottom line, you can't do what you are trying like that. Perhaps reset the pointer.

I'm calling it a night -- 20 questions is out for now. I see what you are saying, but using a separate function makes life so much easier.

This is what I would do (in part).

Code:

char encrypt_char(char src)
{
   static const char source[] = "qazwsxedcrfvtgbyhnujmikolp";   
   static const char target[] = "lkjhgfdsaqwertyuiopmnbvcxz";    
   size_t i;
   for ( i = 0; source[i] != '\0'; ++i )
   {
      if ( src == source[i] )
      {
         return target[i];
      }
   }
   return src; /* someting else */
}

Put that in a simple loop...

Code:

void encrypt_string(const char *src)
{
   for ( ; *src; ++src )
   {
      putchar(encrypt_char(*src));
   }
}

Test it with user input or a canned string.

Such things can be implemented inline in main as well.

src is the character to be converted. if the conversion is not possible (not found) it simply returns the original character.

right. if the code get's that far then the character wasn't found in the lookup table so it's just returned to the caller.