how can i pass this array to my function?

Hello everyone,

I'm given the following main() function and is required to write a function to do things. Could someone please help me with the prototype? Im really stuck and dont know how to pass a string parameter to MyFunc. Thanks in advance!

Code:

---

int main()
{
    char MyString[2][5] = {"1234", "abc5"};
   
    for(i=0;i<2;i++)
        MyFunc(MyString[i]);
 
    return 0;
}

void MyFunc( what_should_i_put_here )
{
    search throw MyString ("1234" and "abc5") to do stuff;
}

---

Try this. I am not sure how well it will work.

Code:

---

void MyFunc(char strings[][]){
          /*Code Here*/
}

---

~Sven

Perhaps this.

Code:

---

#include <stdio.h>

void MyFunc( char *text )
{
  puts(text);
}

int main()
{
    char MyString[2][5] = {"1234", "abc5"};
    int i;
    for ( i = 0; i < 2; ++i )
    {
      MyFunc(MyString[i]);
    }
    return 0;
}

/* my output
1234
abc5
*/

---

Code:

---

void MyFunc( char MyString[2][5] )

---

works too.

Quote:

---

Originally Posted by Dave_Sinkula

Perhaps this.

Code:

---

#include <stdio.h>

void MyFunc( char *text )
{
  puts(text);
}

....

/* my output
1234
abc5
*/

---

---

Thanks so much :). This works perfectly ...Here is what i needed to to (main function is given).

Code:

---

#include <stdio.h>

void MyFNatoi(char *, int *);

int main(void)
{
    char numbers[5][10] = { "123456789", "0001234", "abc5xyz", "012a", "987654321" };
    int i, value;

    for(i=0; i<5; i++)
    {
        MyFNatoi(numbers[i], &value);
        printf("array: '%s' int value: %d\n", numbers[i], value);
    }

    return (0);
}

void MyFNatoi(char *a, int *value)
{
    int number;
    int temp;
    int i=0;

    while(a[i]=='0')
        i++;

    do
    {
            temp=a[i]-'0';
            if(temp>=0 && temp<10)
            {
                number=number*10+temp;
                i++;
            }
            else
                number=0;
    }while( number!=0 && a[i]!='\0' );

    *value=number;
}
Output:
array: '123456789' int value: 123456789
array: '0001234' int value: 1234
array: 'abc5xyz' int value: 0
array: '012a' int value: 0
array: '987654321' int value: 987654321

---

my task was just to write a function to convert character array to integer. Some more examples:

Code:

---

character array ('s'):    integer pointer (*value):
  ----------------------------------------------------
  "abc123"                  0
  "49"                      49
  "678abc"                  0
  ""                        0
  "889123"                  889123

---

Once again, thanks so much :). That was quick replies :).