This is a discussion on Linked list question. within the C Programming forums, part of the General Programming Boards category; For $20 dollars, I'll post all 10,000 lines of this engineering wonder. The question comes on how the node gets ...
For $20 dollars, I'll post all 10,000 lines of this engineering wonder. The question comes on how the node gets allocated.
Maybe I'm being dense, but why not go something like:Code:struct node { int scores; int *next; }; typedef N_TYPE n_type; /*skip 500 lines */ node ->next = malloc(sizeof *node->next);
node->next = malloc(sizeof(struct node));
>> For $20 dollars, I'll post all 10,000 lines of this engineering wonder.
a twenty dollar visual assault? I'll pass.
>> why not go something like:
that would be a clearer way to do it.
Code:int main(void){srand(time(0));for(double l=rand(),l0=0,l00=0;;l0+=0.1){for(double l000=0;l000 <1;l000+=.001,l+=((double)rand()/RAND_MAX)/0x64,l00+=((sin(l*0x8*atan(l0)*l000-(l0*0x8*atan (l)))*0.5)+0.5)){l00-=floor(l00);for(size_t l0000=0,l00000=(size_t)(0x50*(l00));l0000<l00000;++l0000 )putchar(0x20);putchar(0x61+(int)((double)rand()/RAND_MAX*0x1a));putchar('\n');}}return 0;}
So going like
Is supposed to make the intent more clearer than going something likeCode:node ->next = malloc(sizeof *node->next);
Code:node ->next = malloc(sizeof (struct node));
no, I meant the other way around.
Code:int main(void){srand(time(0));for(double l=rand(),l0=0,l00=0;;l0+=0.1){for(double l000=0;l000 <1;l000+=.001,l+=((double)rand()/RAND_MAX)/0x64,l00+=((sin(l*0x8*atan(l0)*l000-(l0*0x8*atan (l)))*0.5)+0.5)){l00-=floor(l00);for(size_t l0000=0,l00000=(size_t)(0x50*(l00));l0000<l00000;++l0000 )putchar(0x20);putchar(0x61+(int)((double)rand()/RAND_MAX*0x1a));putchar('\n');}}return 0;}
Depends on what you mean by "clear". I do agree with you on that one, though.
LinkBack URL
About LinkBacks
