problem with unicode

hello guys,
how do i rectify this problem. i have been trying to use the below code to check the isdigit fucntion, but returns me 0 all the time.

Code:

---

#include<stdio.h>
#include<ctype.h>
#include<locale.h>

int main()
{
    setlocale(LC_CTYPE,"English");
    printf("%d",isdigit(4));
    getchar();
}

---

i am working on DEV-C++ on XP platform

thanks in adavnce

ssharish2005

Perhaps this?

Code:

---

printf("%d",isdigit('4'));

---

thanks Dave_Sinkula for you reply, what happends with the following

Code:

---

#include<stdio.h>
#include<ctype.h>
#include<locale.h>
#include<stdlib.h>

int main()
{
    char sym[] = {"123"};
    setlocale(LC_CTYPE,"English");
    printf("%d",isdigit(atoi(sym)));
    getchar();
    return 0;
}

---

ssharish2005

The printed result would nonzero if the value 123 is an encoding for a digit. In ASCII, for example, digits have encoding values 48-57 inclusive.

but it still prints me 0 even though after changing setting the locale to English. its not encoding in my case. does any one know why??am i setting the locale properly?? thank u very much guys

ssahrish2005

Well you posted incorrect code twice now, so how about posting the results from Dave's code?

Or repost your latest effort.

Because isdigit() is for '0' to '9', not 4 or 123 or any other integer value you get.

Quote:

---

Because isdigit() is for '0' to '9', not 4 or 123 or any other integer value you get.

---

thanks salem for your reply. it seems that isdigit works only for unsigned char. but i was trying to check with a set of unsigned char thats the reason i posted with the set of char 123. its seems that it can work only a single unsigned char. i think i got the answer. thanks salem and Dave. sorry about my miss understanding in the above post.

ssharish2005