Feof replacement

This is a discussion on Feof replacement within the C Programming forums, part of the General Programming Boards category; I have been trying to find a good way to replace feof(); but havn't quite found one. I have been ...

  1. #1
    Registered User 00Sven's Avatar
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    Feof replacement

    I have been trying to find a good way to replace feof(); but havn't quite found one. I have been trying to read a file line by line until i hit the end of the file and then print if out onto the screen. This is what I have:
    Code:
    while(fgets(temp,sizeof(temp),fp)!=NULL){
                                                         fgets(string,sizeof(string),fp);
                                                         puts(string);
    }
    The problem with this is that it gets the last string twice. How do I fix this?
    ~Sven
    Windows XP Home Edition - Dev-C++ 4.9.9.2
    Quote Originally Posted by "The C Programming Language" by Brian W. Kernignhan and Dennis M. Ritchie
    int fflush(FILE *stream)
    On an output stream, fflush causes any buffered but unwritten data to be written; On an input stream, the effect is undefined. It returns EOF for a write error, and zero otherwise. fflush(NULL) flushes all output streams.
    board.theprogrammingsite.com

  2. #2
    Registered User Tonto's Avatar
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    You're doing fgets(..) twice.

  3. #3
    Code Goddess Prelude's Avatar
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    >How do I fix this?
    Only call fgets once?
    Code:
    while(fgets(temp,sizeof(temp),fp)!=NULL){
      puts(temp);
    }
    My best code is written with the delete key.

  4. #4
    Registered User 00Sven's Avatar
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    The first fgets is into temp while the other is into string. So only one fgets is for string. And only the last line is printed twice.
    ~Sven
    Windows XP Home Edition - Dev-C++ 4.9.9.2
    Quote Originally Posted by "The C Programming Language" by Brian W. Kernignhan and Dennis M. Ritchie
    int fflush(FILE *stream)
    On an output stream, fflush causes any buffered but unwritten data to be written; On an input stream, the effect is undefined. It returns EOF for a write error, and zero otherwise. fflush(NULL) flushes all output streams.
    board.theprogrammingsite.com

  5. #5
    Been here, done that.
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    Quote Originally Posted by 00Sven
    The first fgets is into temp while the other is into string. So only one fgets is for string. And only the last line is printed twice.
    ~Sven
    Clarify please. Are you saying your file has exactly an even number of lines? The first line of each pair (line 1, 3, 5...) gets read into temp and the second line of each pair (line 2, 4, 6...) gets read into string?

    What line number is the last line of the file? To work as described it must be even.
    Definition: Politics -- Latin, from
    poly meaning many and
    tics meaning blood sucking parasites
    -- Tom Smothers

  6. #6
    Registered User 00Sven's Avatar
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    OK sorry I get it now and it works. Thanks Prelude!
    ~Sven
    Windows XP Home Edition - Dev-C++ 4.9.9.2
    Quote Originally Posted by "The C Programming Language" by Brian W. Kernignhan and Dennis M. Ritchie
    int fflush(FILE *stream)
    On an output stream, fflush causes any buffered but unwritten data to be written; On an input stream, the effect is undefined. It returns EOF for a write error, and zero otherwise. fflush(NULL) flushes all output streams.
    board.theprogrammingsite.com

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