Thread: Simple int -> char conversion failing...

Hi,
I'm trying to convert an int to a char, just to see if the value entered is a alphabetic character. Here's what I have in my method:

Code:

void FillUserArray( int userArray[], int arraySize )
{
    int i = 0;  //array indexer
    int j = 1;  //counter for output format
    int x;    //holders for user input

    while( i < arraySize )
    {
        printf( "#%d: ", j );
        scanf( "%d", &x );

        userArray(i) = x; //code pasting into forum doesn't allow [ ]

        if( isalpha( (char)x ) )
            printf( "no alpha" );

        if( x < 1 || x > 47 )
        {
            printf( "\nThe number you are entering cannot be less than one, and no greater than forty-seven.\n\n" );
        }
        else if( HasBeenAssigned( userArray, arraySize, x, i ) == x )
        {
            printf( "\nPlease make sure the number you are entering has not already been assigned.\n\n" );
        }
        else
        {
            i++;
            j++;
        }
    }
}

When scanf reads a letter into x, though, it just loops endlessly. How can I detect if the value entered is a character, and then print something if it is?