anyone understand this?

**Da Beav** · 09-03-2001

ok im trying to compile this code from a book and it isnt compiling
here it is:

Code:

if (c == ' ' || c == '\n' || c == '\t')

should be if 'c' is blank , newline or tab but the compiler (dev for windows) is saying "Invalid lvalue in assignment"
any ideas?

Oh and if you need more of it I can post it

**Witch_King** · 09-03-2001

What type is 'c'? If it is a char as in:

Code:

char c;

Than the tests are okay, I think! But if you defined 'c' like this:

Code:

char c[2];

Than you need to use double quotes " " in your test.

Also since I can't see your code, make sure you use the & when you scan the character c in scanf, or else don't use the & if c is a string. Maybe show some more code next time.

Okay for example:

Code:

#include<stdio.h>
int main()
{
  char c;
  scanf("%c",&c);
  if(c== ' ' || c == '\n' || c == '\t') puts("Owtch");
  return 0;
}

Actually it won't work with strings because you have to use the function: strcmp(source,compare); So just use characters instead like in the code above.

**Da Beav** · 09-05-2001

been away for a day or two but here is the entire program:

Code:

#include <stdio.h>

#define IN 1        /*inside a word*/
#define OUT 0     /*outside a word*/

/*count lines, words, and characters in input*/
main ()
{
        int c, nl, nw, nc, state;
        
        state = OUT;
        nl = nw = nc = 0;
        while ((c = getchar()) !=EOF) {
             ++nc;
              if (c =='\n')
                  ++nl;
              if (c == ' ' || c== '\n' || c == '\t')
                   state = OUT;
              else if (state == OUT) {
                    state = IN;
                    ++nw;
               }
          }
        printf ("%d %d %d\n", nl, nw, nc);
}

its still the if (c == ' ' || c == '\n' || c =='\t') line that is causeing me problems (or so my compiler tells me)
thanks for any help on this

**zen** · 09-05-2001

I tried you code on MSVC and Dev C++ and it compiled on both of them.

**Witch_King** · 09-06-2001

I didn't compile the code since zen said that it compiles but this looks like one of those 'clear the standard input buffer' problems.
Inside your while loop, include this code:

Code:

while(getchar() != '\n') continue;

**Xaviar Khan** · 09-06-2001

I compiled this code as well. Compiled with 2 warnings that were easily fixed. Just one question, what exactly are you trying to do with this code. Maybe it can be done another way. There is always another way! (well most times :O)

**biosx** · 09-06-2001

Originally posted by Xaviar Khan
I compiled this code as well. Compiled with 2 warnings that were easily fixed. Just one question, what exactly are you trying to do with this code. Maybe it can be done another way. There is always another way! (well most times :O)

It's an exercise from a book. I recognize it, it's from K&R.

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