Thread: printing days for a particular month

Hey guys just wondering if someone can check my program out iv attached the files its the cal.c program. Im trying to print the days in a month if its 31 days in that month i want it to print the sequence from 1 2 3 4 etc etc to 31

eg if you type cal 1 2006 in unix

January

1 2 3 4 5 6 7
8 9 10 11 12
etc etc

how can i go through the 31 days then print them for each month

Code:

display_month(int st,int n){
printf("\ns  m  t  w  t  f  s" );
printf("\n");
int c= st;
for(int j=1;j<c;j++)printf("   ");
for(int j =1;j<=n;j++){
if(j>9)printf("%d ",j); else
printf("%d  ",j);
c++;
if(c==8){c=1;printf("\n");}
 }
};

try along these lines,
st determines the starting of the month, it is 1 if month starts with a sunday,2 if month starts with a monday and so on.
n is the number of days in the month.

Hey guys could u check out my program again stil a little confused about getting the days for each month for the calendar?

its not working for some reason the way it should for some reason
mon tue wed thu fri sat sun
1 2 3 4 5 6 7
etc etc

Well something like

Code:

int daysInMonth[] = { 31, 28, };
char *monthNames[] = {
  "January",
  "February",
};

Extended of course to fill in the other 10 entries yourself.

Then you can do

Code:

printf( "%s", monthNames[month-1] );