need help printing this pattern

This is a discussion on need help printing this pattern within the C Programming forums, part of the General Programming Boards category; I am having trouble coming up with the function code for this. User will input a size which corresponds to ...

  1. #1
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    need help printing this pattern

    I am having trouble coming up with the function code for this. User will input a size which corresponds to the number of rows and number of columns that will be printed. For example, if the user gives a size of 5, this is what will be printed:

    $$$$$
    $$$$5
    $$$55
    $$555
    $5555

    Any help would be appreciated.

  2. #2
    Devil's Advocate SlyMaelstrom's Avatar
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    Would you happen to know this guy?

    Making a pattern using void()
    Sent from my iPadŽ

  3. #3
    Registered User ssharish2005's Avatar
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    here is a sample code which will print you the above formatted aoutput. it dont ask for any row an coloum input, you got to work through it. think about the code - which bit of the code will change to get your requirenmnet -

    Code:
    #include<stdio.h>
    
    int main()
    {
        int i,j,k;
        
        for(i=0;i<5;i++)
        {
            for(j=5-i;j>0;j--)
                printf("%c",'$');
            for(k=i;k>0;k--)
                printf("%d",5);
            
            printf("\n");
        }
    
        getchar();
        return 0;
    }
    
    /*my ouptput
    $$$$$
    $$$$5
    $$$55
    $$555
    $5555
    */
    ssharish2005

  4. #4
    and the hat of wrongness Salem's Avatar
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    And the spoon-feeder of the week award goes to ....

    How does blurting out the whole answer help the OP understand anything?

    There's every likelyhood that they'll just hand it in without really understanding anything at all, which makes their next assignment all the more difficult.

    Oh well,

  5. #5
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    I wasn't going to post my whole code here because I thought it might be a give away but since it has already been done, I will. I hope that is OK.

    Before I post it, one caveat though...

    I am very new to C. I have been exposed to it for a whole 4 weeks and I've only learnt a few functions and control structures so I am sure that this is nowhere near the best way to do this. If you are learning, you might not want to take much notice of this. Perhaps some of the more experienced people here can offer a comment on what I could have done better.

    Anyway, for what it's worth, here's my code. Please don't laugh...

    Code:
    #include <stdio.h>
    
    int main (void) {
    	int rows, row_num, filled, unfilled, the_num; /* declaring the variables for use in the loops and user entry */
    	char the_char = '$'; /* Declaring the spacer character. As per example, it is set to a $ but could be anything*/
    	
    	/* The user interface bit. Asks for the size of the grid. Works best with numbers 1-9 but will work with any
    number (although the results look weird) */
    	printf("Enter the number of columns/rows: ");
    	scanf("%d", &rows);
    	
    	/* Setting up the values for the variables, at this stage they are all either the same as the number 
    entered by the user or are zero */
    	the_num = rows; /* Used to store the number to print in the grid */
    	filled = 0; /* Used to keep track of how many numbers should appear on the line */
    	unfilled = rows; /* Used to keep track of how many spacer characters are on the line */
    	row_num = 0; /* Used to keep track of which row or line is being printed */
    	
    	/* This is the outer loop. Each loop prints 1 line of $'s and Numbers */
    	while (row_num < rows) {
    		
    		unfilled = (rows - row_num); /* This sets the number of $'s to print to 1 less on each line */
    		
    		/* This is the first of 2 inner loops. This one prints the spacer character ($ in this case) */
    		while (unfilled > 0) {
    			printf ("%c", the_char);
    			unfilled = (unfilled - 1);
    		}
    		
    		filled = row_num; /* This sets the number of numbers to print to 1 more on each line */
    		
    		/* This is the second of the 2 inner loops. This one prints the number */
    		while (filled > 0) {
    			printf("%d", the_num);
    			filled = (filled - 1);
    		}
    		
    		printf("\n"); /* This prints a new line so that, on the next outer loop, the text prints on it's own line */
    		
    		row_num = (row_num + 1); /* Keeps track of how many lines there have been and ends if it reaches the number entered */
    	}
    	
        return 0;
    }
    Well, at least it works.

    I have commented the hell out of it in the hopes that it will help you understand what I've done and why I've done it.

    Any questions or comments? Let me know.
    Last edited by tvsinesperanto; 03-04-2006 at 05:46 AM. Reason: Code was too wide for most sceens. Inserted some <cr>'s

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