This is a discussion on Putchar function within the C Programming forums, part of the General Programming Boards category; hey all, i am a newbie and will appreciate your help with this very beginners thread... i am trying to ...
hey all,
i am a newbie and will appreciate your help with this very beginners thread...
i am trying to write a function that will accept an integer and will print it is ASCII value (after conversion) using putchar.
here is what i have so far:
however this function prints the value of i so if my argument was 3 it prints out 3.Code:int my_itoa(int i) { putchar(i+'0'); }
any idea how to get the ASCII value of 51?
thanks a lot.
no conversion is needed:
putchar(51);
that would print 3.
Code:int main(void){srand(time(0));for(double l=rand(),l0=0,l00=0;;l0+=0.1){for(double l000=0;l000 <1;l000+=.001,l+=((double)rand()/RAND_MAX)/0x64,l00+=((sin(l*0x8*atan(l0)*l000-(l0*0x8*atan (l)))*0.5)+0.5)){l00-=floor(l00);for(size_t l0000=0,l00000=(size_t)(0x50*(l00));l0000<l00000;++l0000 )putchar(0x20);putchar(0x61+(int)((double)rand()/RAND_MAX*0x1a));putchar('\n');}}return 0;}
Since you were adding to the ascii value of 0 and since numbers are in the correct order in ascii that is why a value of 3 outputted the number 3 as 0+3=3Code:putchar(i+'0');
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