Skipping a character?

[kabuatama]

Is there a way to prompt a user for a number, but if the user enters a character such as a letter, to just skip that entry? If it helps, here is the code I have so far:

#include <stdio.h>
#include <math.h>

#define Max_numbers 10

int main(void)

{        
         
         double x[Max_numbers];

                
         int i;
         
         char str[20];

    printf( "Please enter your name:\t " );
    gets(str);
    printf("Hello, %s!\n", str);
    printf("Please Enter %d numbers separated by spaces or returns\n",
                   Max_numbers);
    for (i = 0; i < Max_numbers; ++i) {
        
        scanf("%lf", &x[i]);
        if (x[i] == 0)
     i +=10; }
 


system("Pause");      
                

}

I have it so the program will stop retrieving numbers if the user enters "0". Is an array the best way to do this? Thanks in advance!

[Dave_Sinkula]

FAQ.

[kabuatama]

I checked the FAQ but still couldn't find it. Very sorry, but does anyone have any specific help? It would be greatly appreciated. Thanks.

[Dave_Sinkula]

Sorry, I was thinking of the ones that were about How to Read a String, How to Read a Number (for ints, but the general information can also be applied to floats), Why Not to Use gets, Why using system is not preferred (although apparently the FAQ doesn't mention that). And other stuff like that.

[kabuatama]

I now understand how to test for a number. The problem I am having now is how to simply skip the input if a non-number is entered. Please help me out on this. Thanks.

Edit:

I figured this out, but I am wondering if there is a way to find the smallest value in an array, and then print it out? Basically I have to sort the numbers in the array from smallest to largest.