Why does the code excute, but I get no print message?

This is a discussion on Why does the code excute, but I get no print message? within the C Programming forums, part of the General Programming Boards category; Could someone give me some kind of technical explanation why the follow code will execute, but won't print anything out? ...

  1. #1
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    Why does the code excute, but I get no print message?

    Could someone give me some kind of technical explanation why the follow code will execute, but won't print anything out?

    Code:
    #include <stdio.h>
    #include <signal.h>
    #include <unistd.h>
    
    static void sig_alarm(int signo) {
      if(signo == SIGALRM)
        printf("Signal Caught \n");
    }
    
    unsigned int sleep1(unsigned int nsec){
      if(signal(SIGALRM,sig_alarm) == SIG_ERR){
        return(nsec);
      }
      alarm(nsec);
      pause();
      return(alarm(0));
    }
    
    int main(void) {
      sleep(5);
      return 0;
    }
    Thanks
    Last edited by cdalten; 02-11-2006 at 06:53 AM.

  2. #2
    ZuK
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    Because you call the wrong sleep function
    Code:
    int main(void) {
      sleep1(5);  // not sleep(5)
      return 0;
    }
    Kurt

  3. #3
    Registered User ssharish2005's Avatar
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    you are not calling the fucntion properly. check out the code again. the main cals sleep fucntion. which seems to call sleep1 in your code.

    ssharish2005

  4. #4
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    Yeah, sleep() is actually a function which causes the program to...for lack of a better word sleep, for 5 miliseconds or something or another....which is why the program compiled with no problems. Change the sleep() call in the main to sleep1() and you should be fine.

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