Thread: Newbie question: Problem with malloc

Hi, this code seems to work, but I don't know if it really is working because I get a different size of what I spect. The code is:

Code:

#include <stdlib.h>

int *buff

main(int argc, char argv[])
{
if ((buff = malloc(sizeof(int)*4)) = NULL) {
printf("Malloc didn't work"\n);
} else {
printf("Malloc worked\n");
*buff = 1;
printf("%d\n", *buff);
printf("%d\n", sizeof(buff));

The problem that I have is that didn't understand is the second printf because I expect to be bigger because the call to malloc.
I suppose malloc is working, but don't know what is doing?.

Sorry about the mistake typing the = for the Null, that's ok in my code. But think that the main question you have solve it. Thanks