y does it run fork twice
when i run this code i get the message "this is child1" twice.. its only suppose to run one time?? am i doing anything wrong
pid_t childpid1, childpid2;
printf("Create 2 processes\n");
childpid1 = fork();
childpid2 = fork();
int i = 0;
if (childpid1 == 0 && i==0)
printf("\nthis is child 1\0");
if (childpid2 == 0 && i==1)
printf("\nthis is child 2\0");
> childpid2 = fork();
Because this happens in parent AND child1
> if (childpid2 == 0 && i==1)
Because i is never anything other than 0
> printf("\nthis is child 2\0")
Strings always have a \0, so there's no point in adding another one yourself.
Also, you're writing C99 code, but I don't suppose that matters to you.
yeah i know i isnt anything else then 0, but this is was a test before i added it to my program. II i can see ur point that child 2 is a parent and a child....
thanks... ill fix this straight away
i got nooo idea what c99 code is.. so i guess it doenst matter ;)
This kind of declaration is allowed in C99 but not in previous versions of ansi C (or K&R C). This isn't really an issue unless you try to use a compiler that doesn't support it, but it's nice to know these things in any case.
/* executable code above here */
int i = 0;