this is the o/p;Code:#include <stdio.h> int main() { char c; scanf("%c",&c); printf("%c\n",c); scanf(" %c",&c); //there is a space (" %c" printf("%c\n",c); return 0; }
a
a
b
b
case 2:
o/p:Code:#include <stdio.h> int main() { char c; scanf("%c",&c); printf("%c\n",c); scanf("%c",&c); /////there is no space printf("%c\n",c); return 0; }
a
a
program terminates...doesn't ask for second input ?
help me ....
In version 2 the second scanf returns the '\n' left in the buffer after the first scanf.
in version 1 " %c" (with space ) tells scanf to skip leading whitespace ( '\n' is whitespace )
Kurt
change
Code:scanf("%c",&c); and scanf("%c",&c); to scanf("%s",&c); scanf("%s",&c);
Last edited by cdalten; 01-30-2006 at 08:45 AM.
No, that's wrong. For two reasons:
1 - You don't have an array, so you can't read strings (ie: %s is for strings).
2 - Even if you did have an array, you don't use & with array names to read into a string.
If you did have an array, you might do something like this:Quzah.Code:char buf[ BUFSIZ ] = {0}; ... scanf( "%s", buf );
Hope is the first step on the road to disappointment.
