Hi all,
i have never encounter a code that is written this way. From my experience, isn't a code is suppose to end when ; is encounter? So why is the following code has a \ after ; . can someone explain to me what the following code means?
ThanksCode:#define a (b |= ~c); \ //What is \ after ; (d |= e); \ (f &= ~g); \ (h |= i);