Thread: function

Hi,

i am just not sure whether the below way is valid and usable

I have the following 2 functions :

Code:

        int func1() 
        {
         }


       int func2()
       {
        }

if i do the following , will it valid?

Code:

        func1(func2());

i know that this will work if scanf or printf is used. is it the same concepts?

thks

Code:

#include <iostream>

int function1(int func_return_value);
int function2(int number);

int main()
{
	
	function1(function2(1));

	return 0;
}

int function1(int func_return_value){

	if(func_return_value == 0)
		std::cout<< "Function 2's return value is 0" << std::endl;

	if(func_return_value == 1)
		std::cout<< "Function 2's return value is 1" << std::endl;

	if(func_return_value > 1)
		std::cout<< "Function 2's return value is 2" << std::endl;

	return 0;
}

int function2(int number){

	if(number == 0)
		return 0;
	if(number == 1)
		return 1;

	return 2;
}

There you go give that a shot.

Originally Posted by suzanne_lim

if i do the following , will it valid?

Code:

        func1(func2());

All things being equal, func2() will execute and its return value will become the parameter for func1() ... this is very common.

func2() must have a return value of the appropriate type, of course.

Thanks guy...U saved me