problem with EOF

This is a discussion on problem with EOF within the C Programming forums, part of the General Programming Boards category; Hi,i am writing a program which among the others,it has to store all the words from txt files in a ...

  1. #1
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    problem with EOF

    Hi,i am writing a program which among the others,it has to store all the words from txt files in a hash table.the problem is that the program seems not to find the EOF in the first text,so it stops in that point.i 'm giving the specific part of the code.i will appreciate any help!!
    Code:
    	for(counter=0;counter<p;counter++)
    	{
    		while((c=fgetc(stream[counter]))!=feof(stream[counter]))
    		{
    			i=0;
    			while(c!='\0')
    			{
    				buffer[i]=c;
    				c=fgetc(stream[counter]);
    				printf("%c",buffer[i]);
    				i++;
    			}
    			buffer[i]=(char)"/0";
    		}
    	}

  2. #2
    Registered User hk_mp5kpdw's Avatar
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    The feof function basically returns a yes(nonzero)/no(zero) integer value. The fgetc function returns an integer value cooresponding to the value of the character read from the file or the value EOF to indicate if the end-of-file has been reached. You don't need to call feof at all in your loop, just test the return value from the fgetc function for equality to EOF.

    Code:
    while( (c=fgetc(stream[counter])) != EOF)
    Make sure c is declared as an int and not a char.
    "Owners of dogs will have noticed that, if you provide them with food and water and shelter and affection, they will think you are god. Whereas owners of cats are compelled to realize that, if you provide them with food and water and shelter and affection, they draw the conclusion that they are gods."
    -Christopher Hitchens

  3. #3
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    Code:
    while((c=fgetc(stream[counter]))!=feof(stream[counter]))
    That line of code won't work. What happens if you read a 0 in from the file? Also, feof() returns non-zero when it reaches the end of the file. Why are you comparing that result to the return value of fgetc()?

    I think you meant to do something like:
    Code:
    while((c=fgetc(stream[counter])) && !feof(stream[counter]))
    which can be shortened to:
    Code:
    while((c=fgetc(stream[counter]))!=EOF)

  4. #4
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    thanks for the help,but still nothing !another idea????

  5. #5
    ZuK
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    replace
    Code:
    buffer[i]=(char)"/0";
    with
    Code:
    buffer[i]='\0';
    Kurt

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