Thread: AND OR NOT logical && || !

I am still needing help understanding logical operators.

assuming i = 4 and j = 2 and k = -2
what do the following yield???

Code:

printf("%d ",  !i < j );
printf("%d", !!i < !j );
printf("%d ", i && j || k );
printf("%d", i < j || k );

what does !i mean?
what does !!i mean?
what does !i < j mean?
what does !!i < !j mean?
what does i && j mean?
what does i && j || k mean?

I am confused. When I input the above code in and compiled and ran, I got a result of [size=huge]1[/size] for each print function called.



??

what does !i mean?

well if i is true (anything other than 0) then !i (not i) is false(0) and vice-versa.

what does !!i mean?

not not i so if i is true not not i is true.

what does !i < j mean?

if i is true then !i becomes false and is it less than j? will be a true or false answer.

what does !!i < !j mean?

i think you can do this one now.

what does i && j mean?

are i and j both true. If so true else false.

what does i && j || k mean?

the result of i && j is then ored with k.or will produce true if one or both of its operands are true.

there is a thread on the c++ board about bitwise operators. Read that everything that applies to bits applies to boolean logic just on a slightly different scale.(with logical operators we are not testing/setting individual bits).