printf hex

Hey guys just wondering how i can print a hexadecimal using printf

Use the %x modifier.

Code:

/* har har */
int a = 0x09; /* 9 (hex) */
printf("%d", a); /* outputs 9 (hex) */

Next time, why don't you read some documentation before posting such a question?

http://www.google.com/search?q=printf+hexadecimal

You can try %X also. Try it too...

As with all printf() formatting, you use the correct format template specifier. In the case of hexadecimal, you can use either "%x" or "%X", depending on whether you want the alpha digits to be upper or lower case. To get a particular width, with zero padding on the left, you use something like "%08x" (assuming that you want to print the value as an 8 digit hexadecimal number).

For example:

Code:

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char **argv)
{
    long octval;
    char *octend;
    long decval;
    char *decend;
    long hexval;
    char *hexend;

    if (argc == 2)
    {
        octval = strtol(argv[1], &octend, 8); /* read as octal */
        decval = strtol(argv[1], &decend, 10); /* read as decimal */
        hexval = strtol(argv[1], &hexend, 16); /* read as hexadecimal */

        printf("The string '%s' can be interpreted thus:\n", argv[1]);
        printf("   Oct: %011o (dec %d, hex %08x, %d chars)\n",
                 octval, octval, octval, (int)(octend - argv[1]));
        printf("   Dec: %d (oct %011o, hex %08x, %d chars)\n",
                 decval, decval, decval, (int)(decend - argv[1]));
        printf("   Hex: %08x (oct %011o, dec %d, %d chars)\n",
                 hexval, hexval, hexval, (int)(hexend - argv[1]));
    }
    else
    {
        printf("Usage: %s valuestring\n", argv[0]);
    }
    return 0;
}

Originally Posted by cwr

Code:

/* har har */
int a = 0x09; /* 9 (hex) */
printf("%d", a); /* outputs 9 (hex) */

I think your reply is a bit confusing.

Code:

int a = 0x0a;
printf("%d",a);  /* outputs 10 (decimal)
printf("0x%x",a); /* outputs 0xa */

I think the original OP is looking how to print out the hex value, as shown by other posters you can use the %x modifier.

Originally Posted by slcjoey

I think your reply is a bit confusing.

Code:

int a = 0x0a;
printf("%d",a);  /* outputs 10 (decimal)
printf("0x%x",a); /* outputs 0xa */

I think the original OP is looking how to print out the hex value, as shown by other posters you can use the %x modifier.

duh. lol
did you notice the "har har" comment?