Thread: help on simple program

i was wondering if yas could help me with this simple code that i can't get around. There are 2 problems. First i dont know how to ask the password in a way so that ****** will come up on the screen when being typed in. Second of all, i noticed that after the third attempt at the password, if you enter it incorrect, the password will be accepted by passing progress onto the next statement, where i would prefer if the program exited? Heres the code. cheers !

#include <stdio.h>
#include <conio.h>
#include <string.h>

int password(void);

int main()
{
int choice; //variable called choice of type integer
password(); //Calls password function

cprintf("\nAccess accepted !");
getch();
}
int password(void)
{

//Variables
char passwd[10];
int count, correct = 0;

for(count=0;count<3;count++) /*Give user three attempts*/
{
clrscr(); //Call the clear screen function
gotoxy(21,8);
cprintf("**** PASSWORD IS CASE SENSITIVE ****");
gotoxy(26,10);
cprintf("Please Enter Password : ");
cscanf("%s",passwd);
if(strcmp("GOD", passwd)==0)
{
count=3; //Breaks out of for loop
correct = 1; //Allows user into system
}
else
{
gotoxy(25,12);
correct = 0; //Does not allow user into system
textcolor(WHITE); //Sets font colour to white
cprintf("Incorrect Password Entered!!!");
gotoxy(29,13);
cprintf("%d attempt(s) left",3-(count+1));
gotoxy(25,14);
cprintf("Press any key to continue....");
getch(); getch();
}
}
return correct;
}

I think you need to assign the "int" returned from password() to a variable in main and then use an "if" statement to examine the return value and do an "exit" if the user didn't "pass" the password test. Of course, you would also then need to modify the password() function to return a value other than "correct" if the user reaches 3 tries. Hope that helps.

You don't necessarily need another variable to hold the return value from the password() function.

int main()
{
int choice; //variable called choice of type integer

if (password()) //Calls password function
{
cprintf("\nAccess accepted !");
}
else
{
cprintf("invalid password");
exit(1) // or some value that is appropriate
}

getch();
}