How to delete part of an array?

In one tutorial I downloaded, it said use "delete [] arrayname", but when I attempted to compile, it said "delete function undefined" or something to that effect. So I tried this:

Code:

char myname[4] = "ash";
ash[1] = ""; //trying to delete the s
printf("%s", ash);

but when it printed, it printed "a*h" (in place of the asterick it had some other weird symbol that I have no idea how to reproduce here ) So I guess I'm just asking if someone can tell me how to delete a single element of a string array. (I assume it's the same for a non-string array too). Also I see that you can't put a space in that way either..., I tried ash[1] = " "; so it should print "a h", but instead it has that weird character again....

Thanks for any help, I promise that once I start to learn more of c i'll ask more complicated stupid questions

delete
That is C++ .. decide whether you want to code in C or C++ and post in the appropriate forum.

> In one tutorial I downloaded, it said use "delete [] arrayname"
1. That delete is C++, this is the C forum
2. You can only delete what you got from doing new.

Basically, to remove an element from an array, you need to manually shuffle down all the following elements, so

Code:

ash[1] = ash[2];
ash[2] = ash[3];

Naturally, a for loop would make this a lot easier.

Or even using the standard function memmove() if you get bored of writing too many loops.

Don't use something like strcpy( &ash[1], &ash[2] ). Nearly all the standard functions are undefined if the memory blocks overlap, as in this case. memmove() is a specific exception which works properly even with overlapping memory ranges.

delete is a C++ keyword, and with a [] context, it means to deallocate something that was previously pointing to an array, I think. It doesn't exist in C.

Anyway, you can't "delete an array", and you can't "delete part of an array". An array has a fixed size, all you can do is change the values inside. In the context of what you are asking above, you actually want to replace the s with a space, so ash[1] = ' '; (note single quotes) would suffice. Your double quote efforts won't work, they are for string literals, not characters.

Ping, my mistake, I didn't know it was a c++ keyword. I am actually just trying to learn c, sorry 'bout that.

Salem & cwr - thanks again to both y'all for the help, it is *greatly* appreciated.

Code:

#include<stdio.h>

int main()
{
      char myname[4] = "ash";
      ash[1] = " "; //need to give space in between
      printf("%s", myname);
      getchar();
      return 0;
}

/*myoutput
a h
*/

ssharish2005

Originally Posted by ssharish2005

Code:

#include<stdio.h>

int main()
{
      char myname[4] = "ash";
      ash[1] = " "; //need to give space in between
      printf("%s", myname);
      getchar();
      return 0;
}

/*myoutput
a h
*/

ssharish2005

That code is wrong. For a start, ash is undeclared. Also, it should be ' ' not " ".

Originally Posted by cwr

That code is wrong. For a start, ash is undeclared. Also, it should be ' ' not " ".

So what you're really saying is:

Originally Posted by ssharish2005

/*myoutput
a h
*/

Should read something like:

Originally Posted by ssharish2005

/*myoutput
myout.c: In function `main':
myout.c:6: error: `ash' undeclared (first use in this function)
myout.c:6: error: (Each undeclared identifier is reported only once
myout.c:6: error: for each function it appears in.)
myout.c:6: error: parse error before '/' token
myout.c:5: warning: unused variable `myname'
*/

Quzah.

sorry i thought i could just type the code but it end up with the disaster sorry about that here is a compiled code

Code:

#include<stdio.h>

int main()
{
    char str[4] = {"ash"};

    str[1] = ' ';
    printf("%s",str);
    getchar();
}
/*my outout
a h
*/

NOTE: it shouldn't be " " it should be ' ' cose it's just a single char rather than stringssharihs

the solution to the problem i figured out ,is as follows

/*Program ----> deleting a part of an array */
/*In this program we are going to delete 'd'
key idea --->make the adderess of 'd' point to the next , and the next to the next
From -----------> Ekarshi Mitra (Btech ------1Year----CSIT)
Date -----------> 1-01-2006
Time -----------> 11:45 P.M*/

Code:

#include <stdio.h>
#include <string.h>
int main ()/*void main() can also be used , depends unpon programmer*/

{
    char name[]="under test";
    int marker=2,count,string_length=strlen(name);
     
    /*now suppose we remove 'd' from under test*/
    for(count=marker;count<string_length;count++)
    {
                                                    name[count]=(int)*&name[count+1];/*typecasting done here*/
                                                 /* can be compiled removing (int) */
                                                 }
                                                 printf(" ans = %s",name);
                                                 getchar();
                                                 return 0;
                                                 }
/*compiled and run under devc++ (IDE) */

> /*void main() can also be used , depends unpon programmer*/
As in clueless ?

> name[count]=(int)*&name[count+1];/*typecasting done here*/
Well that was pointless. Since the * and & cancel out, why not just write the bloody obvious
name[count]=name[count+1];

Removing an element from an array is easy, but it does not change the size of the array. You would have to remove the element, re-allocate a new array the size you need, copy the current elements from the old one to the new one, point your pointer to the new one, de-allocate the old one.

A pain in the butt. If you want a better approach to dynamic arrays, move to C++ STL and use a vector.