strcat the inside of a structure

**ebullient** · 12-09-2005

i want to concatenate a string to a structure passed in the parameter and return the new structure. and it works if i pass it by reference and use pointers,

for example,

Code:

typedef struct
{
    char someString[80];
}someStruct;



someStructMore(someStruct);

int main
{
    someStruct blah;
    /*etc assignments to blah*/
    someStruct more(someStruct blah);
    return 0;
}


someStruct more(someStruct blah);
{
    someStruct value;
    char aLine[80] = "Heya person.";

  ....

}

And what I'd like to do is

strcat(blah.someString, aLine);
strcat(more.someString, blah.someString);

But I get compiling issues. I understand that strcat concatenates a string to a pointer, meaning I can't just use blah.someString or more.someString, so I am now wondering how I'd be able to get around that issue but using something other than strcat(). Any ideas?

**quzah** · 12-09-2005

Code:

strcat( foo.bar, "something" ); /*directly*/
strcat( foo->bar, "something" ); /*via a pointer*/

Quzah.

**ebullient** · 12-09-2005

I understand how to use the pointer option, but I want to change the actual value without having to use it.

I get compiling issues if I do,

Code:

strcat(foo.bar, "string");

**Dave_Sinkula** · 12-09-2005

It's easier to start from a real example rather than a paraphrased one.

Code:

#include <stdio.h>
#include <string.h>

struct type
{
    char text[80];
};

struct type foo(struct type copy)
{
   struct type newobj;
   strcpy(newobj.text, copy.text);
   strcat(newobj.text, "strcat ");
   return newobj;
}

int main(void)
{
    struct type a = {"start "};
    struct type b = foo(a);
    struct type c = foo(b);
    puts(a.text);
    puts(b.text);
    puts(c.text);
    return 0;
}

/* my output
start 
start strcat 
start strcat strcat 
*/

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