invalid operands to binary %

Code:

#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#define MAXZO 100

void findMinValue(int n, int *zo, int *tail)
{
	unsigned long i, j, d, zoValue;
	for (i = 0; i < MAXZO; i++)
		zo[i] = 0;
	*tail = (int)log(n);
	zo[*tail] = 1;
	do {
		zoValue = n;
		i = 0;
		while (zo[i] == 2) {
			zo[i] = 0;
			zo[++i]++;
		}
		if (*tail > MAXZO) exit(0);
		if (zo[*tail+1] == 1) *tail++;
		for (i = 0; i <= *tail; i++) {
			if (zo[i] == 1) {
				d = pow(10, (int)log(n)+1) % n;
				for (j = i; j <= (int)i/log(n); j++)
					zoValue = (zoValue*d) % n;
			}
			zoValue = (zoValue*pow(10, n-(int)i/log(n))) % n;
		}
		printf("%d\n", zoValue);
		zo[0]++;
	} while (zoValue != 0);
}

int main()
{
	FILE *fr, *fw;
	int n, tail, i;
	int zo[MAXZO];
	fr = fopen("02.dat", "rt");
	fw = fopen("02.out", "wt");
	fscanf(fr, "%d", &n);
	findMinValue(n, zo, &tail);
	for (i = 0; i <= tail; i++) 
		fprintf(fw, "%d", zo[i]);
	fclose(fr);
	fclose(fw);
	return 0;
}

I just want to use module operator. But it didn't work.

Code:

mathsniper:~# gcc -O2 -o 02 02.c -lm
02.c: In function ‘findMinValue’:
02.c:24: error: invalid operands to binary %
02.c:28: error: invalid operands to binary %

The % operator does not work with doubles, which pow returns.

One example of your problem is this line;

Code:

d = pow(10, (int)log(n)+1) % n;

as pow() returns a double. The % operator is only defined for integral types (int, long, unsigned, etc) and has no defined meaning for floating point types.

To get a sort-of equivalent functionality for arguments of type double, look up the function fmod() which is declared in <math.h>

The problem was solved. Thanks.