Deleting element from an array problem

xamlit · 12-03-2005, 01:17 PM

Hey guys!,

I am trying to remove a user specified element from the display of an array. I know that this doesn't take it out of the array, but I figure that if I get this it would be the same process copying it to a temp array and then back.

Code:

printf("Please enter number to delete");
   scanf("%d",&d);
   
   printf("\n\n\nModified list:");
   
   for (i=0;i<x;i++) 
   {   
       if (i = d) 
       {
             i = i+1;
       }
       else 
       {
       printf("%s",words[i]);
       }
}

**Salem** · 12-03-2005, 01:34 PM

> if (i = d)
Perhaps == instead of =

Didn't your compiler warn you?

Are you using a compiler which is capable of warning you?

PING · 12-03-2005, 01:42 PM

You need not start from 0, if the user inputs the number into the variable d, just start out with that number itself.

Code:

for(i=d;i<MAX-1;i++)
array[i]=array[i+1];

xamlit · 12-03-2005, 02:59 PM

Quote:

Originally Posted by PING

You need not start from 0, if the user inputs the number into the variable d, just start out with that number itself.

Code:

for(i=d;i<MAX-1;i++)
array[i]=array[i+1];

Hmm.. but doesn't that just start from the element they entered? I want to be able to display all the elements as if it were removed. such as :

1.box
2.shoe
3.red
4.crayon

user selects to delete red from the display, new display should look like this:

1.box.
2.shoe
3.crayon

I hope I'm making this clear enough.

I appreciate any help you give me.

PING · 12-03-2005, 04:50 PM

just replace this

Code:

array[i]=array[i+1];

by this

Code:

strcpy(array[i],array[i+1]);

This is valid considering that you are using a 2d char array to store the different strings.

dwks · 12-03-2005, 04:53 PM

And you should set array[0] to something, too.

Code:

if (i = d)

->

Code:

if (i == d)

12-03-2005, 01:17 PM	#1
xamlit Registered User Join Date: Jul 2005 Posts: 10	Deleting element from an array problem Hey guys!, I am trying to remove a user specified element from the display of an array. I know that this doesn't take it out of the array, but I figure that if I get this it would be the same process copying it to a temp array and then back. Code: printf("Please enter number to delete"); scanf("%d",&d); printf("\n\n\nModified list:"); for (i=0;i<x;i++) { if (i = d) { i = i+1; } else { printf("%s",words[i]); } }
xamlit is offline

12-03-2005, 01:34 PM	#2
Salem and the hat of Jobseeking Join Date: Aug 2001 Location: The edge of the known universe Posts: 21,710	> if (i = d) Perhaps == instead of = Didn't your compiler warn you? Are you using a compiler which is capable of warning you?
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12-03-2005, 01:42 PM	#3
PING Registered User Join Date: Nov 2004 Location: india Posts: 493	You need not start from 0, if the user inputs the number into the variable d, just start out with that number itself. Code: for(i=d;i<MAX-1;i++) array[i]=array[i+1]; __________________ Go Petr !! My Blog
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12-03-2005, 04:50 PM	#5
PING Registered User Join Date: Nov 2004 Location: india Posts: 493	just replace this Code: array[i]=array[i+1]; by this Code: strcpy(array[i],array[i+1]); This is valid considering that you are using a 2d char array to store the different strings. __________________ Go Petr !! My Blog
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12-03-2005, 04:53 PM	#6
dwks Frequently Quite Prolix Join Date: Apr 2005 Location: Canada Posts: 7,698	And you should set array[0] to something, too. Code: if (i = d) -> Code: if (i == d) __________________ dwk Seek and ye shall find. quaere et invenies. "Simplicity does not precede complexity, but follows it." -- Alan Perlis "Testing can only prove the presence of bugs, not their absence." -- Edsger Dijkstra "The only real mistake is the one from which we learn nothing." -- John Powell Other boards: DaniWeb, TPS Unofficial Wiki FAQ: cpwiki.sf.net My website: http://dwks.theprogrammingsite.com/ Projects: codeform, xuni, atlantis, nort, etc.
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