Thread: looping quest..

do u mean soemthing like this

Sampe code

Code:

#include<stdio.h>

int main()
{
 	int ch;
 	
 	printf("1. Add values\n");
 	printf("2. Sub values\n");
	printf("3. Mul Values\n");
	printf("4. Exit\n");
	
	printf("\nEnter your choice\n");
	scanf("%d",&ch);
	
	while(ch!=4)
	{
	 		switch(ch)
			 {
				  case 1:
				   	 /*do something here*/
			 break;
			      case 2:
					/* do something here*/
			 break;
				case 3:
				                /* do soemthing here */
			 break;
			 }
				 printf("1. Add values\n");
 				 printf("2. Sub values\n");
			 	 printf("3. Mul Values\n");
				 printf("4. Exit\n");
	
				 printf("\nEnter your choice\n");
				 scanf("%d",&ch);
    }
    
    getchar();
    return 0;
}

ssharish2005

Nice indentation, ssharish2005! And did you ever consider using a do-while loop or something to eliminate the duplicate code?

I would re-write the above code to look like this:

Code:

#include <stdio.h>

int main(void) {
    int ch, c

    while(ch != 4) {
        printf("1. Add values\n");
        printf("2. Sub values\n");
        printf("3. Mul Values\n");
        printf("4. Exit\n");
	
        printf("\nEnter your choice\n");
        scanf("%d",&ch);

        while((c = getchar()) != '\n' && c != EOF);

        switch(ch) {
        case 1:
            /*do something here*/
            break;

        case 2:
            /* do something here*/
            break;

        case 3:
            /* do something here */
            break;

        default: break;
        }
    }

    getchar();
    return 0;
}

Code:

int main(void) {
    int ch, c

    while(ch != 4)

ch contains the garbage value.It may contain 4.

I'd use dwks' solution but with a do-while loop instead to eliminate the chance that ch starts off with the value 4:

Code:

do
{
// blah blah blah
} while(ch != 4);

Oops, yeah, I forgot a semicolon and stuff, the line was supposed to be like this:

Code:

int ch = 0, c;