Thread: switch statements

is there anyway to make a switch statement run forever instead of just breaking if one case is satisfied

JUst don't use a break statement?

Sample Code

Code:

#include<stdio.h>

int main()
{
 	switch(1)
 	{
	 		 case 1:
			 	  printf("One\t");
	 	     case 2:
			 	  printf("Two\t");
 		     case 3:
			 	  printf("Three\t");
	  		 case 4:
			 	  printf("Four\t");
    }

	getchar();
	return 0;
} 
/* myoutput
One     Two     Three   Four
*/

ssharish2005

Originally Posted by ssharish2005

Sample Code

Code:

#include<stdio.h>

int main()
{
 	switch(1)
 	{
	 		 case 1:
			 	  printf("One\t");
	 	     case 2:
			 	  printf("Two\t");
 		     case 3:
			 	  printf("Three\t");
	  		 case 4:
			 	  printf("Four\t");
    }

	getchar();
	return 0;
} 
/* myoutput
One     Two     Three   Four
*/

ssharish2005

That is called "fall through" and I am not sure if that is what he really wants with "run forever" as this will run one time only.
However, this will run forever. The switch block is inside of the while block that runs forever.. that gives you a chance to read a new value into n or compute n, etc. Otherwise, what would be the point?

Code:

while ( 1 ) {    /* Run forever. . . */
    /* variable n can be computed here, etc. */
    
    switch ( n ) {
    case 0:
        /* code */
        break;
    
    case 1:
        /* code */
        break;
    
    case 2:
        /* code */
        break;
    }
}