I am trying to build a HANGMAN program. I want to first ask the user to enter a word, and then I want that word to be the word that you have to guess. My problem is I don't understand how to make an array the same size as the number of letters of whatever the word is.
Any help is appreciated!
char *word;
/* Get input from user and store it in a "large enough" buffer called input */
word = malloc(strlen(input) + 1);
strcpy(word, input);
/* When done with the word... */
free(word);
If you understand what you're doing, you're not learning anything.
I forgot to mention, I'm not allowed to use strings for the assignment.
Are arrays of characters allowed, but strings not allowed?
Here is a lame attempt so far of what I'm trying to do
Code:#include <stdio.h> #define SIZE 20 #define GUESS '*' int main(void) { char word[SIZE]; int i; char ch; int status; printf("Enter a word > "); scanf("%d", &word[i]); status = i; printf(" %d", status); while(status == 1) { word[i] = status; ++i; status = scanf(" %c", &ch); } return(0); }
Last edited by 1rwhites; 11-08-2005 at 05:01 PM.
I don't understand how to figure out how many letters are in the word the user enters.
Last edited by 1rwhites; 11-08-2005 at 05:02 PM.
I see a number of problems here.
won't work as you'd expect -- even assuming that you put the comma between the format string and the target ('scanf(" %c", &data)), you're telling it to skip a space in the input then give you one character, not a word.Code:scanf(" %c" &data);
Your function get_data() makes no real sense to me at all.
I would suggest sitting down and writing out your algorithm (a flow-chart of the program is a good idea in any case) and then work out what the code should look like. Once you know how you want the program to work, you can (if you need to) ask specific questions about how do do specific things. For now, I don't think you're on the right track.
In my program, I want the user to enter a word. After that, I need for my program to tell me how many letters the user entered. I know I need some sort of an array, and I'm not allowed to use strings.
Does anybody know how to do this?
Thanks in advance.
Something like this?
[edit]How exactly do you intend to have an array of characters that is not a string, unless you simply mean to use a non-null-terminated char array (which is just a pain in the ass)?Code:#include <stdio.h> int main(void) { int ch, count = 0; fputs("Enter a word: ", stdout); fflush(stdout); while ( (ch = getchar()) != '\n' && ch != EOF ) { ++count; } printf("You entered a %d-letter word (which I just discarded).\n", count); return 0; } /* my output Enter a word: hello You entered a 5-letter word (which I just discarded). */
Last edited by Dave_Sinkula; 11-08-2005 at 05:36 PM.
7. It is easier to write an incorrect program than understand a correct one.
40. There are two ways to write error-free programs; only the third one works.*
Easy way using command line arguments.
Code:#include <stdio.h> int main(int argc, char **argv) { if(argc != 2){ printf("Use: <%s> <word>\n", argv[0]); return -1; } printf("%s is %d characters long\n", argv[1], strlen(argv[1])); return 0; }
I like to play pocket pool.
Is there anyways I can do that without using "stdout"?
Here is what I have so far...
I want to have an array "guess" that will take the number of letters of the word the user enters and make them *'s. So for example the user enters word. I want the guess array to look like ****Code:#include <stdio.h> #define SIZE 20 char word[SIZE]; char guess[SIZE]; #define STAR '*' int main (void) { printf("Enter a word > "); int i = 0; do { word[i]=getchar(); i++; } while (word[i-1] != '\n'); int num_stars = i - 1; printf("%d", num_stars); char search; printf("\nGuess a letter > "); scanf("%c", &search); for( i = 0; i < SIZE; i++ ) { if( word[i] == search ) break; } if( i == SIZE ) printf("%c was not found!", search); else printf("%c = %c and was located at position %d\n\n", search, word[i], i); return 0; }
Can anybody help me with this?
Stop making new threads. Damn. You do know you can reply in the same thread don't you? You have three of them now.
Quzah.
Hope is the first step on the road to disappointment.
Please keep all questions regarding the same issue to the same thread
Look out! This is a string:
And so is this:"%d"
And this!"\nGuess a letter > "
And don't forget these:"%c"
"can't use strings" is a ridiculous limitation, but it's possible and your program is still using them."%c was not found!"
"%c = %c and was located at position %d\n\n"
If you understand what you're doing, you're not learning anything.
