c help arrays

[tmitch]

I am a newbie trying create an array that will sum the row and columns. I have been able to get them to display,but not total. Any help would be great.

#include <stdio.h>
void main(void)
{
  int val[5][5] = {8,3,9,0,10,
                   3,5,17,1,1,
                  2,8,6,23,1,
	       15,7,3,2,9,
	       6,14,2,6,0};
  void display (int nums[5][5]);  /* function prototype */

  display(val);
}
void display(int nums[5][5])

{
  int row_num, col_num;
  for (row_num = 0; row_num <5; ++row_num)
  {
    for(col_num = 0; col_num <5; ++col_num)
      printf("%5d",nums[row_num][col_num]);
    printf("\n");
}
}

[Barnzey]

So want every part of the array to be sumed with all the other parts, if not can you say it again, i didnt really understand.

[tmitch]

I need to know how to total all the rows and columns in the arrays

[Dave_Sinkula]

Something like this.

#include <stdio.h>

void display(int nums[5][5])
{
   int r, c;
   for ( r = 0; r < 5; ++r )
   {
      int sum = 0;
      for ( c = 0; c < 5; ++c )
      {
         printf("%5d ", nums[r][c]);
         sum += nums[r][c];
      }
      printf("sum = %d\n", sum);
   }
}

int main(void)
{
   int val[5][5] =
   {
      {8,3,9,0,10},
      {3,5,17,1,1},
      {2,8,6,23,1},
      {15,7,3,2,9},
      {6,14,2,6,0},
   };
   display(val);
   return 0;
}

/* my output
    8     3     9     0    10 sum = 30
    3     5    17     1     1 sum = 27
    2     8     6    23     1 sum = 40
   15     7     3     2     9 sum = 36
    6    14     2     6     0 sum = 28
*/

[sahil_m]

Hi,

I have made some changes to your program, read my comments.

#include <stdio.h>

int display (int nums[5][5]);  /*This function will return the total*/ 

int main(void)   /*main should ALWAYS return an integer*/
{
  int val[5][5] = {8,3,9,0,10,
                          3,5,17,1,1,
                          2,8,6,23,1,
	          15,7,3,2,9,
	          6,14,2,6,0};
  int total;
  
  total=display(val);   /*Returned back total from display*/
  
  printf("\nTotal is:%d",total);
  
  return 0;      /*Since main was defined as int main(void) */ 


}

int display(int nums[5][5])  /*This line was causing trouble*/

{
  int row_num, col_num;
  int total=0;         /*This variable will hold your total*/

  for (row_num = 0; row_num <5; ++row_num)
  {
    for(col_num = 0; col_num <5; ++col_num)
    {
      
        printf("%5d",nums[row_num][col_num]);

        total = total + nums[row_num][col_num]; /*total calc */
    
   }
 }
  
 return total;   /*Returning total back to main*/
}

Make sure you go through this program and understand what's going on.

[tmitch]

Hi Sahil I am getting the folowing errors. I am using VB to compile.

compiling...
summ arrayhelp.cpp
c:\program files\microsoft visual studio\myprojects\prob2-float\summ arrayhelp.cpp(25) : error C2556: 'void __cdecl display(int [][5])' : overloaded function differs only by return type from 'int __cdecl display(int [][5])'
c:\program files\microsoft visual studio\myprojects\prob2-float\summ arrayhelp.cpp(3) : see declaration of 'display'
c:\program files\microsoft visual studio\myprojects\prob2-float\summ arrayhelp.cpp(25) : error C2371: 'display' : redefinition; different basic types
c:\program files\microsoft visual studio\myprojects\prob2-float\summ arrayhelp.cpp(3) : see declaration of 'display'
Error executing cl.exe.

summ arrayhelp.obj - 2 error(s), 0 warning(s)

[sahil_m]

Oh!, I am sorry I made a typo, but you should have figured that out yourself, the function prototype and the definition dont match, I am fixing that right now.

[tmitch]

thanks, I didn't catch it