Runtime problem

This is a discussion on Runtime problem within the C Programming forums, part of the General Programming Boards category; Hello I wrote this code it's meant to convert a mathematical from 1 form to another but I cannot enter ...

  1. #1
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    Runtime problem

    Hello I wrote this code it's meant to convert a mathematical from 1 form to another but I cannot enter the numarator and the denominator sepeartly please help me as I'am out of ideas of what to do to solve it.

    Code:
    #include <stdio.h>
    
    
    int main()
    {
    	char z,w,G,num,den;
    	float Ts;
    	
    w=z-1/Ts;
    
    G=num/den;
    
    printf("Please enter the samplling rate: ");
    scanf("%f",&Ts);
    	
    printf("Please enter the numarator in terms of w: ");
    scanf("%c",&num);
    
    printf("Please enter the denominator in terms of w: ");
    scanf("%c",&den);
    
    printf("The discrete transfer function in the form of Z is %c \n",G);
    
    return 0;
    }

  2. #2
    cwr
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    %c is for a character. That is, if you enter the number 5, it will read the character '5', which probably translates to the value 53 on most systems. You're better off just using an int type and %d.

    Also, why are you assigning w dependent on the values of the not yet initialised values of Ts and z?

  3. #3
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    also change the data type of those variables from char to int. %d works with pointers to int, not pointers to char.

  4. #4
    cwr
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    %d works with pointers to int, not pointers to char.
    That's why I said "You're better off just using an int type and %d"

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