Functions

[Unregistered]

I need main() to pass a string and int num to a function only once then the function must set up a loop that will print that string
num number of times - want to know if this code is right.

void james (int,char[]);
void main (void)
{
james(5,"hooman");
}
void james (int num, char name[])
{
int i;
for(i=1;i<=num;++i)
printf("%s\n",name);
}

[Stoned_Coder]

looks fine except for the void main bit...
try this:-

void james (int,char[]); 
int main (void) 
{ 
james(5,"hooman");
return 0; 
} 
void james (int num, char name[]) 
{ 
int i; 
for(i=1;i<=num;++i) 
printf("%s\n",name); 
}

[Witch_King]

This notation works technically:

for(i=1;i<=num;++i)

But is better represented by:

for(i=0;i<num;++i)

[bigtamscot]

Hi, Only problem I can see with your code is the incrementation in the for loop..... ++i will increment i before the first loop...therefore
1 becomes 2 and the name will only print 4 times...be better to use i++, which increments i after statements within the loop are processed...
for(i = 1, i <= num, i++)
Also if you want to print name 5 times as in your code, it would be better to initialize i to 0 and get rid of the "=" in the conditional......
for ( i = 0; i < num; i ++)

[Salem]

> want to know if this code is right.
Get a compiler and ask it

> ++i will increment i before the first loop...therefore
No it won't.
The increment step is performed at the end of the loop, assuming the loop is executed at all by evaluation of the control expression.

for ( i = 0 ; i < num ; i++ )
for ( i = 0 ; i < num ; ++i )
for ( i = 1 ; i <= num ; i++ )
for ( i = 1 ; i <= num ; ++i )
All run the same number of iterations.