simplify this?

This is a discussion on simplify this? within the C Programming forums, part of the General Programming Boards category; Code: #include <stdio.h> void main() { int matrix[100][100], n, k, l, bord, bord1, bord2, bord3, bord4; do{ printf("Enter order of ...

  1. #1
    Registered User
    Join Date
    Oct 2005
    Posts
    6

    simplify this?

    Code:
    #include <stdio.h>
    
    void main()
    {
    	int matrix[100][100], n, k, l, bord, bord1, bord2, bord3, bord4;
    
    	do{
    		printf("Enter order of matrix between 1 and 100 \n");
    		scanf("%d",&n);
    	}while(n<1 || n>100);
    
    	for(k=0;k<n;k++){
    		printf("Enter values for Row %d\n",k);
    		for(l=0;l<n;l++){
    			printf("Enter values for row %d col %d\n",k,l);
    			scanf("%d",&matrix[k][l]);
    		}
    	}
    	bord=0;
    	for(k=0;k<1;k++){
    		for(l=0;l<n;++l){
    			bord=bord+matrix[k][l];
    		}
    	}
    	bord1=0;
    	for(k=n-1;k<n;k++){
    		for(l=0;l<n;++l){
    			bord1=bord1+matrix[k][l];
    		}
    	}
    	bord2=0;
    	for(l=0;l<1;l++){
    		for(k=0;k<n;k++){
    			bord2=bord2+matrix[k][l];
    		}
    	}
    	bord3=0;
    	for(l=n-1;l<n;l++){
    		for(k=0;k<n;k++){
    			bord3=bord3+matrix[k][l];
    		}
    	}
    	bord4=0;
    	bord4=bord+bord1+bord2+bord3;
    	printf("The sum of the border elements are: %d\n",bord4);
    }
    I'm supposed to make a square matrix n x n, and get the sum of all border elements. This program is what I came up with, it works well enough, I was just wondering if there was a way to use fewer iterative statements.
    Last edited by markg; 10-25-2005 at 08:05 PM. Reason: missed bord2

  2. #2
    End Of Line Hammer's Avatar
    Join Date
    Apr 2002
    Posts
    6,231
    Forgetting the setup process, the addition of all the sides can be peformed using only one loop. For now, I'll leave it to you to figure out how

    Also, are you sure your program does what you want? I entered a 2x2 matrix, each cell containing the value 1, and it told me the sum was 6:
    Code:
    Enter order of matrix between 1 and 100
    2
    Enter values for Row 0
    Enter values for row 0 col 0
    1
    Enter values for row 0 col 1
    1
    Enter values for Row 1
    Enter values for row 1 col 0
    1
    Enter values for row 1 col 1
    1
    The sum of the border elements are: 6
    When all else fails, read the instructions.
    If you're posting code, use code tags: [code] /* insert code here */ [/code]

  3. #3
    Registered User
    Join Date
    Oct 2005
    Posts
    6
    Code:
    bord2=0;
    	for(l=0;l<0;l++){ /*changed it to 1*/
    		for(k=0;k<n;k++){
    			bord2=bord2+matrix[k][l];
    Thanks.

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