Thread: Compiler Issues

I have tried to compile. Need for project. It is supposed to provide error message, but just sits there. Does anyone see what the problem is?

Code:

/*Library for program functions*/
#include <stdio.h>

	/* This declares the atoffunction*/
double atof(char *);

	/*Main Function*/
int main (void)
{
	
	/*Declaration of Currency Conversions*/
	int choice;
	float money;
	float total;
        char ch;
	char input[10];
	int idx, decimal_found ;


	/*Declaration of conversion rates retrieved October 6,2005 on http://www.xe.com/ucc/ and Print*/
	printf("\n\nCURRENCY CONVERSION\n");
	printf("1. British Pound 0.56767=1 U.S. Dollar\n");
	printf("2. Euro 0.83598 =1 U.S. Dollar\n");
	printf("3. Japanese Yen 114.000=1 U.S. Dollar\n");
	printf("4. Mexican Peso 10.71900=1 U.S. Dollar\n");
	printf("5. Russian Ruble 28.56000=1 U.S. Dollar\n");
	printf("Enter the number for the currency to convert...");

	/*Prompt user for Type of Currency */
	printf("\n\n Please Select the Currency you would like to convert (1-5): ");
	scanf("%d",&choice);
	fflush(stdin);
	
	
{	

            char ch;
	char input[10];
	int idx, decimal_found ;

	}
	printf("\n\n Please enter a dollar amount you would like to convert. (US Dollars): ");
	scanf("%f",&money);
	
	decimal_found = 0 ;

	/*Checks for validity of input entered by user for numerical value,retreived from Aruna Pandey*/
 	for (idx = 0 ; idx < strlen(input) ; idx++)
        {
            if (input[idx] == '.')
            {
                // check if more than one decimal character has been entered?
                // if the decimal character was found earlier, the "decimal_found" 
                // flag will be equal to 1. At this time, this is an invalid entry.
                // so exit immediately.
                //
                if (decimal_found == 1)
                    break ;
                else
                    decimal_found = 1 ;
            }
            else
            {
                if (input[idx] < 48 || input[idx] > 57)
                    break ;
            }
 
         }
	/*Checks for non numeric character*/
        if (idx < strlen(input))  
        {
	/*Prints response for invalid entry*/
            printf("Invalid Entry. Please Try Again.\n");
        }
        else
        {
            /* converts user input to a float value*/
            &money = atof(input); 
           

	/*Returns Selected Choice with Currency Conversion*/
         }
	if(choice == 1)
	{
		total = money * 0.56767;
		printf("\n\nYou will have %f British Pounds \n\n", total);
	}
	if(choice == 2)
	{
		total = money * 0.83598;
		printf("\n\nYou will have %f Euro \n\n", total);
	}
	if(choice == 3)
	{
		total = money * 114.000;
		printf("\n\nYou will have %f Japansese Yen \n\n",total);
	}
	if(choice == 4)
	{
		total = money * 10.71900;
		printf("\n\nYou will have %f Mexican Pesos \n\n", total);
	}
	if(choice == 5)
	{
		total = money * 28.56000;
		printf("\n\nYou will have %f Russian Ruble \n\n", total);
	}

	getchar();

	/*normal program end*/
	return 0;
}

Originally Posted by Ancient Dragon

your compiler should have produced a few syntax errors. never attempt to run a program that cannot be compiled without errors. If your compiler did not produce any errors, then you need to get a different compiler or increase its error/warning levels.

example

Code:

 &money = atof(input);

The above makes no sense at all and most (if not all) c compilers should complain bitterly to you.

The compiler is producing error
&money should be the input?

Originally Posted by marliwht

The compiler is producing error
&money should be the input?

remove the & symbol from money.

Code:

money = ...