hi guys i want to do the following code but it wont work
basically what i want it to do is if the array history[0][1] has nothing in it (which i thought meant null) then i want want to do something. the compiler keeps giving me an error that i can use binary operators on history[0][1].Code:if(history[0][1] == NULL) printf("this worked");
p.s the history array is of type struct history_entry which i have defined my self.
A test against NULL is a test used for pointers, to see if they point at something. So, unless you have a two dimensaional array of pointers, the test is invalid.
Quzah.
Hope is the first step on the road to disappointment.
How did you define history in the first place?
Did you initialise it?
Is history an array of pointers (NULL is for the 'empty' pointer)
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
C has no value which represents a lack of a value. In short, this means that there is no way to check if an object does not have a value because it always does. You might need to rewrite your program based on this new tidbit of knowledge.
alright thanks guys i just initialized the part of the structure im comparing to NULL and it solved the problem
