Command line argument question

I'm having trouble getting a reference to the WHOLE character that is passed through command line. Since argv's is made out of chars, i can't seem to get a get the whole string so i can further manipulate it using fopen.

If i have the following:

Code:

int main(int argc, char *argv[])

i can just print is using

Code:

printf("%s", argv[1])

This is self explanatory , simply because "%s" joins the chars of argv.

Which works fine....
However if i use:

Code:

File = fopen ( argv[1] , "r" );

The first character (i.e. if i enter filename, f is passed to fopen).

So my question is how do i create a char that contains the whole passed in argument?

Not so, in the above fopen call, the whole string of argv[1] is passed.

essentially, fopen accepts a char as a parameter (from what i read)
so if i do: printf("\n%c", argv[1]);

It's basically the same thing as the fopen call therefore it just prints out the first character

hmm never mind.

No, fopen accepts a char pointer to a null terminated string. Why would fopen accept a single character for a filename?