How to enable %zu ??

Hello, Dear all. I am using Dev-C++ 4.9.9.2. My question is how to enable %zu .
The following program prints `zu' instead of an integer, which is what I expect.
How can I set up Dev-C++ to support %zu ?

Code:

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#include <stdio.h>

int main( void )
{
    printf( "%zu", sizeof(int) );
   
    getchar();
}

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I don't think those are supported in printf like that. Why not just use %d instead like this:

Code:

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printf("%d",sizeof(int));

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C99 introduced %z for proper output of size_t types, just in case %d isn't appropriate. I'm not familiar with Dev-C++, perhaps it doesn't come with a C99 library?

To my knowledge it does not come with it.

if you are using a feature of C99, make sure your file type is .c and not .cpp, also make sure your compiler supports it of course.

Yes, my file type is .c . But I'm not sure whether Dev-C++ is fully support C99 or not.

http://groups.google.com/group/comp....2be25e6821e18f

I found that gcc3.2 supports %zu.
So I guess if I set it up correctly, Dev-C++ will support %zu too.

Quote:

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Originally Posted by Dave_Sinkula

http://groups.google.com/group/comp....2be25e6821e18f

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Maybe:

Quote:

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[...] the "%zu" format is new in C99. That means that some systems don't yet support it. (Incidentally, there is no "gcc printf man page". printf is part of the runtime library; gcc is just the compiler. gcc typically uses the native runtime library on a given system, so having a current version of gcc is no guarantee that printf() supports "%zu".)

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